Home > Aptitude and Reasoning > SIMPLE INTEREST COMPOUND INTERESTS PROBLEM WITH EXPLANATIONS

SIMPLE INTEREST COMPOUND INTERESTS PROBLEM WITH EXPLANATIONS

simple and compound interest problems with solutions pdf

QUANTITATIVE APTITUDE SIMPLE COMPOUND INTEREST PRACTICE PROBLEM WITH SOLUTION

Simple Interest Compound Interest Problems With Solutions PDF Download

Complete Quantitative Aptitude eBook from fdaytalk is available free in Amazon kindle and PDF download available in Google Play Book Store

Note: Due to some limitations in web options, Math symbols, notations were unable to view properly. In our eBook all Math symbols, notations will be in order., check preview

All Topics Quantitative Aptitude eBook (569+ Practice Problems with Solutions) PDF download link available in Fdaytalk Book Store, Click Here

SIMPLE INTEREST:
S. I = PTR / 100
S. I = Simple interest
P = principal
T = time in years
R = rate of interest
A = P + S. I
A = total amount

COMPOUND INTEREST:
C. I = P × (1 + R / 100)T – P

C.I = Compound interest
P = principal
T = time in years
R = rate of interest
A = P + C. I
A = Total amount

Compound interest for half-yearly
I = P × (1 + R/2 * 100)2T – P
Compound interest for quarterly
I = P × (1 + R/4 * 100)4T – P
When T = 2 years, R = any rate of interest
I – S. I = PR² / 100²
When T = 3 years, R = any rate of interest
I – S. I = PR² (300 + R) / 100³

Q. The difference between Compound and Simple rates of interest on 10, 000/- for 3 – years at 5% per annum is ………..
SOL:
SHORT METHOD
for Difference between C. I & S. I for 3 – years
C. I – S. I = PR² (300 + R) / 100³
= 10,000 * 5 * 5 * (300 + 5) / 100³
= 76. 25 (answer)

SHORT METHODS FOR COMPOUND INTEREST
When T = 2 years R = any rate of interest

For example R = 6%
C. I = P * 12.36 / 100 [ 12 = 6 + 6 ] [ 36 = 6 * 6 ]
I = Compound interest
P = principal
For example R = 8%
When T = 3 years, R = 3%
C. I = P × 9.2727 / 100

When = 3 years, R = 4%
C. I = P × 12.4864 / 100

When T = 3 years, R = 5%
C. I = P × 15.7625 / 100

When T = 3 years, R = 6%
C. I = P × 19.1016 / 100

When T = 3 years, R = 7%
C. I = P × 22.5043 / 100

When T = 3 years, R = 8%
C. I = P × 25.9712 / 100

When T = 3 years, R = 9%
C. I = P × 29.5029 / 100

When T = 3 years, R = 10%
C. I = P × 33.1 / 100

When T = 3 years, R = 11%
C. I = P × 36.7631 / 100

When T = 3 years, R = 12%
C. I = P × 40.4928 / 100

When T = 3 years, R = 13%
C. I = P × 44.2897 / 100

When T = 3 years, R = 14%
C. I = P × 48.1544 / 100

When T = 3 years, R = 15%
C. I = P × 52.0875 / 100

Practice Simple and Compound Interest Problems

1) On simple interest, any amount becomes 812/- in two years and 924/- in four years. What is the rate of interest on that amount?

2) A man deposits am amount of 54600/- at an S.I rate of 12% for 3 years. What total amount will he get at the end of 3 years?

3) A sum of money will become 108800/- in four years at 7% per annum on S.I. Find the sum ………..

4) A sum of money will become double in 3 years at a certain rate of C.I. In what time will it becomes four times itself ?

5) What will be the amount on 25000/- in 2 years at C.I if the rates for the successive years be 4% & 5% per year

6) The difference of S.I on 5000/- from two banks in 2 years is 100/-. Find the difference of their rate …

7) A sum becomes 3 times in 10 years. In how many years will amount to 5 times at the same rate of S.I

8) Find the sum which amount to 1125/- in 5 years and becomes 1200/- in 8 years at the rate of S.I ………

9) If 5, 000/- becomes 5, 700/- in one year, what will 7, 000/- become at the end of 5- years at the same rate of simple interest?

10) A sum of money 12, 000/- deposited at compound interest became double after 5- years. How much will it be after 20 years ?

11) If the difference between the C. I, compounded every 6 months and the S.I on certain sum of money at the rate of 12% p. a for one year is 36/-, the sum is?

12) Arun lends 20, 000/- to two of his friends. He gives 12, 000/- to the first one at 8% per annum at simple interest. Arun wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is…

13) An amount of money at C. I grow up to 3840/- in 4- years and up to 3956/- in 5- years. Find the rate of interest

14) A man borrows 21, 000/- at 10% compound interest. How much he has to pay equally at the end of each year, to settle his loan in two years is

15) 1, 500/- is invested at a rate of 10% S. I and interest is added to the principal after every 5- years. In how many years will it amount to 2, 500/-?

16) What annual payment will discharge a debt of 6450/- due in 4- years at 5% per annum simple interest?

17) A person invested in three banks in the ratio of 1: 2: 3 and the rates were in the ratio of 2: 3: 4 at S.I, also he got the income in the ratio of 3: 4: 5, then find the ratio of time periods

18) Person invested in all 2, 600/- at 4%, 6% and 8% per annum S.I. At the end of the year, he got the same interest in all three cases. The money invested at 4% is

19) A person has 5, 000/-. He invests a part of it at 3% per annum and the remainder at 8% per annum S.I. His total income I 3- years is 750/-. Find the sum invested at different rate of interest.

20) The S.I and C.I on a sum of money for are 8, 400/- and 8652/- respectively. The rate of interest per annum is

21) A sum of money invested at C.I amounts to 800/- in 2- years and 880/- in 3- years. Find the rate of interest per annum and the sum

22) A man borrows 3000/- at 10% compound rate of interest. At the end of each year he pays back 1000/-, how much amount should he pay at the end of the third year to clear all his dues.

23) A certain sum is invested for certain time. It amounts to 450/- at 7% per annum. But, when invested at 5% per annum, it amounts to 350/-. Find out the sum and time.

24) A sum 2/- is lent to be paid back in 3 equal monthly installments of 1/- each. Find the rate percent ….

25) A man borrows 3, 000/- at 10% compound interest per annum. At the end of each year, he pays back 1,000/-. How much amount he pay at the end of 3rd year to clear all his dues?

26) Divide 15, 494/- A and B so that A’s share at the end of 9 – years may be equals to B’s share at the end of 11 – years, Compound Interest being 20% per annum. Then A’s share is

27) The Simple Interest for 4 –years is one-fourth of the Principal. The sum that will be amount to 450/- in two years at the same rate is

28) Kartik lost 9% by selling pencils at the rate of 15 a rupee. How many for a rupee must Kartik sell them to gain 5%

Solutions for Practice Problems will be available on Fdaytalk Quantitative Aptitude Book, Download Here

Learn More

Link: More Topics in Quantitative Aptitude

Link: Updated GK 2020

Link: Monthly Current Affairs Download

Learn More
simple interest problems with solutions, simple interest problems pdf, simple interest problems with solutions pdf, simple interest problems for class 8, simple interest problems in aptitude, simple interest problems math, simple interest problems practice, simple interest problems, hard simple interest problems, calculating simple interest word problems, simple interest problems in maths, simple interest problems and solutions, simple interest problems with soln, compound interest problems, compound interest problems with solutions pdf, compound interest problems for bank exams, compound interest problems and answers, compound interest problems with short tricks, compound interest problems fractional years, simple and compound interest problems with solutions pdf

Comments